I have been working on Jeandel-Rao tiles lately.

Before the conference Model Sets and Aperiodic Order held in Durham UK (Sep 3-7 2018), I thought it would be a good idea to bring some real tiles at the conference. So I first decided of some conventions to represent the above tiles as topologically closed disk basically using the representation of integers in base 1:

With these shapes, I created a 33 x 19 patch. With 3cm on each side, the patch takes 99cm x 57cm just within the capacity of the laser cut machine (1m x 60 cm):

With the help of David Renault from LaBRI, we went at Coh@bit, the FabLab of Bordeaux University and we laser cut two 3mm thick plywood for a total of 1282 Wang tiles. This is the result:

One may recreate the 33 x 19 tiling as follows (note that I am using
Cartesian-like coordinates, so the first list `data[0]` actually is the first
column from bottom to top):

sage: data = [[10, 4, 6, 1, 3, 3, 7, 0, 9, 7, 2, 6, 1, 3, 8, 7, 0, 9, 7], ....: [4, 5, 6, 1, 8, 10, 4, 0, 9, 3, 8, 7, 0, 9, 7, 5, 0, 9, 3], ....: [3, 7, 6, 1, 7, 2, 5, 0, 9, 8, 7, 5, 0, 9, 3, 7, 0, 9, 10], ....: [10, 4, 6, 1, 3, 8, 7, 0, 9, 7, 5, 6, 1, 8, 10, 4, 0, 9, 3], ....: [2, 5, 6, 1, 8, 7, 5, 0, 9, 3, 7, 6, 1, 7, 2, 5, 0, 9, 8], ....: [8, 7, 6, 1, 7, 5, 6, 1, 8, 10, 4, 6, 1, 3, 8, 7, 0, 9, 7], ....: [7, 5, 6, 1, 3, 7, 6, 1, 7, 2, 5, 6, 1, 8, 7, 5, 0, 9, 3], ....: [3, 7, 6, 1, 10, 4, 6, 1, 3, 8, 7, 6, 1, 7, 5, 6, 1, 8, 10], ....: [10, 4, 6, 1, 3, 3, 7, 0, 9, 7, 5, 6, 1, 3, 7, 6, 1, 7, 2], ....: [2, 5, 6, 1, 8, 10, 4, 0, 9, 3, 7, 6, 1, 10, 4, 6, 1, 3, 8], ....: [8, 7, 6, 1, 7, 5, 5, 0, 9, 10, 4, 6, 1, 3, 3, 7, 0, 9, 7], ....: [7, 5, 6, 1, 3, 7, 6, 1, 10, 4, 5, 6, 1, 8, 10, 4, 0, 9, 3], ....: [3, 7, 6, 1, 10, 4, 6, 1, 3, 3, 7, 6, 1, 7, 2, 5, 0, 9, 8], ....: [10, 4, 6, 1, 3, 3, 7, 0, 9, 10, 4, 6, 1, 3, 8, 7, 0, 9, 7], ....: [4, 5, 6, 1, 8, 10, 4, 0, 9, 3, 3, 7, 0, 9, 7, 5, 0, 9, 3], ....: [3, 7, 6, 1, 7, 2, 5, 0, 9, 8, 10, 4, 0, 9, 3, 7, 0, 9, 10], ....: [10, 4, 6, 1, 3, 8, 7, 0, 9, 7, 5, 5, 0, 9, 10, 4, 0, 9, 3], ....: [2, 5, 6, 1, 8, 7, 5, 0, 9, 3, 7, 6, 1, 10, 4, 5, 0, 9, 8], ....: [8, 7, 6, 1, 7, 5, 6, 1, 8, 10, 4, 6, 1, 3, 3, 7, 0, 9, 7], ....: [7, 5, 6, 1, 3, 7, 6, 1, 7, 2, 5, 6, 1, 8, 10, 4, 0, 9, 3], ....: [3, 7, 6, 1, 10, 4, 6, 1, 3, 8, 7, 6, 1, 7, 2, 5, 0, 9, 8], ....: [10, 4, 6, 1, 3, 3, 7, 0, 9, 7, 2, 6, 1, 3, 8, 7, 0, 9, 7], ....: [4, 5, 6, 1, 8, 10, 4, 0, 9, 3, 8, 7, 0, 9, 7, 5, 0, 9, 3], ....: [3, 7, 6, 1, 7, 2, 5, 0, 9, 8, 7, 5, 0, 9, 3, 7, 0, 9, 10], ....: [10, 4, 6, 1, 3, 8, 7, 0, 9, 7, 5, 6, 1, 8, 10, 4, 0, 9, 3], ....: [3, 3, 7, 0, 9, 7, 5, 0, 9, 3, 7, 6, 1, 7, 2, 5, 0, 9, 8], ....: [8, 10, 4, 0, 9, 3, 7, 0, 9, 10, 4, 6, 1, 3, 8, 7, 0, 9, 7], ....: [7, 5, 5, 0, 9, 10, 4, 0, 9, 3, 3, 7, 0, 9, 7, 5, 0, 9, 3], ....: [3, 7, 6, 1, 10, 4, 5, 0, 9, 8, 10, 4, 0, 9, 3, 7, 0, 9, 10], ....: [10, 4, 6, 1, 3, 3, 7, 0, 9, 7, 5, 5, 0, 9, 10, 4, 0, 9, 3], ....: [2, 5, 6, 1, 8, 10, 4, 0, 9, 3, 7, 6, 1, 10, 4, 5, 0, 9, 8], ....: [8, 7, 6, 1, 7, 5, 5, 0, 9, 10, 4, 6, 1, 3, 3, 7, 0, 9, 7], ....: [7, 5, 6, 1, 3, 7, 6, 1, 10, 4, 5, 6, 1, 8, 10, 4, 0, 9, 3]]

The above patch have been chosen among 1000 other randomly generated as the closest to the asymptotic frequencies of the tiles in Jeandel-Rao tilings (or at least in the minimal subshift that I describe in the preprint):

sage: from collections import Counter sage: c = Counter(flatten(data)) sage: tile_count = [c[i] for i in range(11)]

The asymptotic frequencies:

sage: phi = golden_ratio.n() sage: Linv = [2*phi + 6, 2*phi + 6, 18*phi + 10, 2*phi + 6, 8*phi + 2, ....: 5*phi + 4, 2*phi + 6, 12/5*phi + 14/5, 8*phi + 2, ....: 2*phi + 6, 8*phi + 2] sage: perfect_proportions = vector([1/a for a in Linv])

Comparison of the number of tiles of each type with the expected frequency:

sage: header_row = ['tile id', 'Asymptotic frequency', 'Expected nb of copies', ....: 'Nb copies in the 33x19 patch'] sage: columns = [range(11), perfect_proportions, vector(perfect_proportions)*33*19, tile_count] sage: table(columns=columns, header_row=header_row) tile id Asymptotic frequency Expected nb of copies Nb copies in the 33x19 patch +---------+----------------------+-----------------------+------------------------------+ 0 0.108271182329550 67.8860313206280 67 1 0.108271182329550 67.8860313206280 65 2 0.0255593590340479 16.0257181143480 16 3 0.108271182329550 67.8860313206280 71 4 0.0669152706817991 41.9558747174880 42 5 0.0827118232955023 51.8603132062800 51 6 0.108271182329550 67.8860313206280 65 7 0.149627093977301 93.8161879237680 95 8 0.0669152706817991 41.9558747174880 44 9 0.108271182329550 67.8860313206280 67 10 0.0669152706817991 41.9558747174880 44

I brought the \(33\times19=641\) tiles at the conference and offered to the first 7 persons to find a \(7\times 7\) tiling the opportunity to keep the 49 tiles they used. 49 is a good number since the frequency of the lowest tile (with id 2) is about 2% which allows to have at least one copy of each tile in a subset of 49 tiles allowing a solution.

A natural question to ask is how many such \(7\times 7\) tilings does there
exist? With ticket #25125 that was merged in Sage 8.3 this Spring, it is
possible to enumerate and count solutions in parallel with Knuth dancing links
algorithm. After the installation of the Sage Optional package slabbe (`sage
-pip install slabbe`), one may compute that there are 152244 solutions.

sage: from slabbe import WangTileSet sage: tiles = [(2,4,2,1), (2,2,2,0), (1,1,3,1), (1,2,3,2), (3,1,3,3), ....: (0,1,3,1), (0,0,0,1), (3,1,0,2), (0,2,1,2), (1,2,1,4), (3,3,1,2)] sage: T0 = WangTileSet(tiles) sage: T0_solver = T0.solver(7,7) sage: %time T0_solver.number_of_solutions(ncpus=8) CPU times: user 16 ms, sys: 82.3 ms, total: 98.3 ms Wall time: 388 ms 152244

One may also get the list of all solutions and print one of them:

sage: %time L = T0_solver.all_solutions(); print(len(L)) 152244 CPU times: user 6.46 s, sys: 344 ms, total: 6.8 s Wall time: 6.82 s sage: L[0] A wang tiling of a 7 x 7 rectangle sage: L[0].table() # warning: the output is in Cartesian-like coordinates [[1, 8, 10, 4, 5, 0, 9], [1, 7, 2, 5, 6, 1, 8], [1, 3, 8, 7, 6, 1, 7], [0, 9, 7, 5, 6, 1, 3], [0, 9, 3, 7, 6, 1, 8], [1, 8, 10, 4, 6, 1, 7], [1, 7, 2, 2, 6, 1, 3]]

This is the number of distinct sets of 49 tiles which admits a 7x7 solution:

sage: from collections import Counter sage: def count_tiles(tiling): ....: C = Counter(flatten(tiling.table())) ....: return tuple(C.get(a,0) for a in range(11)) sage: Lfreq = map(count_tiles, L) sage: Lfreq_count = Counter(Lfreq) sage: len(Lfreq_count) 83258

Number of other solutions with the same set of 49 tiles:

sage: Counter(Lfreq_count.values()) Counter({1: 49076, 2: 19849, 3: 6313, 4: 3664, 6: 1410, 5: 1341, 7: 705, 8: 293, 9: 159, 14: 116, 10: 104, 12: 97, 18: 44, 11: 26, 15: 24, 13: 10, 17: 8, 22: 6, 32: 6, 16: 3, 28: 2, 19: 1, 21: 1})

How the number of \(k\times k\)-solutions grows for k from 0 to 9:

sage: [T0.solver(k,k).number_of_solutions() for k in range(10)] [0, 11, 85, 444, 1723, 9172, 50638, 152244, 262019, 1641695]

Unfortunately, most of those \(k\times k\)-solutions are not extendable to a tiling of the whole plane. Indeed the number of \(k\times k\) patches in the language of the minimal aperiodic subshift that I am able to describe and which is a proper subset of Jeandel-Rao tilings seems, according to some heuristic, to be something like:

[1, 11, 49, 108, 184, 268, 367, 483]

I do not share my (ugly) code for this computation yet, as I will rather share clean code soon when times come. So among the 152244 about only 483 (0.32%) of them are prolongable into a uniformly recurrent tiling of the plane.

]]>Compiling sage takes a while and does a lot of stuff. Each time I am wondering
which components takes so much time and which are fast. I wrote a module in my
slabbe version `0.3b2` package available on PyPI to figure this out.

This is after compiling 7.5.beta6 after an upgrade from 7.5.beta4:

sage: from slabbe.analyze_sage_build import draw_sage_build sage: draw_sage_build().pdf()

From scratch from a fresh git clone of 7.5.beta6, after running `MAKE='make
-j4' make ptestlong`, I get:

sage: from slabbe.analyze_sage_build import draw_sage_build sage: draw_sage_build().pdf()

The picture does not include the start and ptestlong because there was an error compiling the documentation.

By default, `draw_sage_build` considers all of the logs files in
`logs/pkgs` but options are available to consider only log files created in a
given interval of time. See `draw_sage_build?` for more info.

Yesterday I received this email (in french):

Salut, avec Thomas on a une question bête: K.<x>=NumberField(x*x-x-1) J'aimerais multiplier une matrice avec des coefficients en x par un vecteur contenant des variables a et b. Il dit "unsupported operand parent for *, Matrix over number field, vector over symbolic ring" Est ce grave ?

Here is my answer. Indeed, in Sage, symbolic variables can't multiply with elements in an Number Field in x:

sage: x = var('x') sage: K.<x> = NumberField(x*x-x-1) sage: a = var('a') sage: a*x Traceback (most recent call last) ... TypeError: unsupported operand parent(s) for '*': 'Symbolic Ring' and 'Number Field in x with defining polynomial x^2 - x - 1'

But, we can define a polynomial ring with variables in a,b and coefficients in
the NumberField. Then, we are able to multiply `a` with `x`:

sage: x = var('x') sage: K.<x> = NumberField(x*x-x-1) sage: K Number Field in x with defining polynomial x^2 - x - 1 sage: R.<a,b> = K['a','b'] sage: R Multivariate Polynomial Ring in a, b over Number Field in x with defining polynomial x^2 - x - 1 sage: a*x (x)*a

With two square brackets, we obtain powers series:

sage: R.<a,b> = K[['a','b']] sage: R Multivariate Power Series Ring in a, b over Number Field in x with defining polynomial x^2 - x - 1 sage: a*x*b (x)*a*b

It works with matrices:

sage: MS = MatrixSpace(R,2,2) sage: MS Full MatrixSpace of 2 by 2 dense matrices over Multivariate Power Series Ring in a, b over Number Field in x with defining polynomial x^2 - x - 1 sage: MS([0,a,b,x]) [ 0 a] [ b (x)] sage: m1 = MS([0,a,b,x]) sage: m2 = MS([0,a+x,b*b+x,x*x]) sage: m1 + m2 * m1 [ (x)*b + a*b (x + 1) + (x + 1)*a] [ (x + 2)*b (3*x + 1) + (x)*a + a*b^2]

These is a summary of the functionalities present in slabbe-0.2.spkg optional
Sage package. It works on version 6.8 of Sage but will work best with sage-6.10
(it is using the new code for `cartesian_product` merged the the betas of
sage-6.10). It contains 7 new modules:

finite_word.pylanguage.pylyapunov.pymatrix_cocycle.pymult_cont_frac.pyxranking_scale.pytikz_picture.py

**Cheat Sheets**

The best way to have a quick look at what can be computed with the optional
Sage package `slabbe-0.2.spkg` is to look at the 3-dimensional Continued
Fraction Algorithms Cheat Sheets available on the arXiv since today. It
gathers a handful of informations on different 3-dimensional Continued Fraction
Algorithms including well-known and old ones (Poincaré, Brun, Selmer, Fully
Subtractive) and new ones (Arnoux-Rauzy-Poincaré, Reverse, Cassaigne).

**Installation**

sage -i http://www.slabbe.org/Sage/slabbe-0.2.spkg # on sage 6.8 sage -p http://www.slabbe.org/Sage/slabbe-0.2.spkg # on sage 6.9 or beyond

**Examples**

Computing the orbit of Brun algorithm on some input in \(\mathbb{R}^3_+\) including dual coordinates:

sage: from slabbe.mult_cont_frac import Brun sage: algo = Brun() sage: algo.cone_orbit_list((100, 87, 15), 4) [(13.0, 87.0, 15.0, 1.0, 2.0, 1.0, 321), (13.0, 72.0, 15.0, 1.0, 2.0, 3.0, 132), (13.0, 57.0, 15.0, 1.0, 2.0, 5.0, 132), (13.0, 42.0, 15.0, 1.0, 2.0, 7.0, 132)]

Computing the invariant measure:

sage: fig = algo.invariant_measure_wireframe_plot(n_iterations=10^6, ndivs=30) sage: fig.savefig('a.png')

Drawing the cylinders:

sage: cocycle = algo.matrix_cocycle() sage: t = cocycle.tikz_n_cylinders(3, scale=3) sage: t.png()

Computing the Lyapunov exponents of the 3-dimensional Brun algorithm:

sage: from slabbe.lyapunov import lyapunov_table sage: lyapunov_table(algo, n_orbits=30, n_iterations=10^7) 30 succesful orbits min mean max std +-----------------------+---------+---------+---------+---------+ $\theta_1$ 0.3026 0.3045 0.3051 0.00046 $\theta_2$ -0.1125 -0.1122 -0.1115 0.00020 $1-\theta_2/\theta_1$ 1.3680 1.3684 1.3689 0.00024

**Dealing with tikzpictures**

Since I create lots of tikzpictures in my code and also because I was unhappy
at how the `view` command of Sage handles them (a tikzpicture is not a math
expression to put inside dollar signs), I decided to create a class for
tikzpictures. I think this module could be useful in Sage so I will propose
its inclusion soon.

I am using the standalone document class which allows some configurations like the border:

sage: from slabbe import TikzPicture sage: g = graphs.PetersenGraph() sage: s = latex(g) sage: t = TikzPicture(s, standalone_configs=["border=4mm"], packages=['tkz-graph'])

The `repr` method does not print all of the string since it is often very
long. Though it shows how many lines are not printed:

sage: t \documentclass[tikz]{standalone} \standaloneconfig{border=4mm} \usepackage{tkz-graph} \begin{document} \begin{tikzpicture} % \useasboundingbox (0,0) rectangle (5.0cm,5.0cm); % \definecolor{cv0}{rgb}{0.0,0.0,0.0} ... ... 68 lines not printed (3748 characters in total) ... ... \Edge[lw=0.1cm,style={color=cv6v8,},](v6)(v8) \Edge[lw=0.1cm,style={color=cv6v9,},](v6)(v9) \Edge[lw=0.1cm,style={color=cv7v9,},](v7)(v9) % \end{tikzpicture} \end{document}

There is a method to generates a pdf and another for generating a png. Both
opens the file in a viewer by default unless `view=False`:

sage: pathtofile = t.png(density=60, view=False) sage: pathtofile = t.pdf()

Compare this with the output of `view(s, tightpage=True)` which does not
allow to control the border and also creates a second empty page on some
operating system (osx, only one page on ubuntu):

sage: view(s, tightpage=True)

One can also provide the filename where to save the file in which case the file is not open in a viewer:

sage: _ = t.pdf('petersen_graph.pdf')

Another example with polyhedron code taken from this Sage thematic tutorial Draw polytopes in LateX using TikZ:

sage: V = [[1,0,1],[1,0,0],[1,1,0],[0,0,-1],[0,1,0],[-1,0,0],[0,1,1],[0,0,1],[0,-1,0]] sage: P = Polyhedron(vertices=V).polar() sage: s = P.projection().tikz([674,108,-731],112) sage: t = TikzPicture(s) sage: t \documentclass[tikz]{standalone} \begin{document} \begin{tikzpicture}% [x={(0.249656cm, -0.577639cm)}, y={(0.777700cm, -0.358578cm)}, z={(-0.576936cm, -0.733318cm)}, scale=2.000000, ... ... 80 lines not printed (4889 characters in total) ... ... \node[vertex] at (1.00000, 1.00000, -1.00000) {}; \node[vertex] at (1.00000, 1.00000, 1.00000) {}; %% %% \end{tikzpicture} \end{document} sage: _ = t.pdf()

Some years ago, I wrote code in Sage to solve the Quantumino puzzle. I also used it to make a one-minute video illustrating the Dancing links algorithm which I am proud to say it is now part of the Dancing links wikipedia page.

Let me recall that the goal of the Quantumino puzzle is to fill a \(2\times
5\times 8\) box with 16 out of 17 three-dimensional pentaminos. After writing
the sage code to solve the puzzle, one question was left: how many solutions
are there? Is the official website realist or very prudent when they say
that *there are over 10.000 potential solutions*? Can it be computed in hours?
days? months? years? The only thing I knew was that the following computation
(letting the 0-th pentamino aside) never finished on my machine:

sage: from sage.games.quantumino import QuantuminoSolver sage: QuantuminoSolver(0).number_of_solutions() # long time :)

Since I spent already too much time on this side-project, I decided in 2012 to stop investing any more time on it and to really focus on finishing writing my thesis.

So before I finish writing my thesis, I knew that the computation was not going to take a light-year, since I was able to finish the computation of the number of solutions when the 0-th pentamino is put aside and when one pentamino is pre-positioned somewhere in the box. That computation completed in 4 hours on my old laptop and gave about 5 millions solutions. There are 17 choices of pentatminos to put aside, there are 360 distinct positions of that pentamino in the box, so I estimated the number of solution to be something like \(17\times 360\times 5000000 = 30 \times 10^9\). Most importantly, I estimated the computation to take \(17\times 360\times 4= 24480\) hours or 1020 days. Therefore, I knew I could not do it on my laptop.

But last year, I received an email from the designer of the Quantumino puzzle:

-------- Message transféré -------- Sujet : quantumino Date : Tue, 09 Dec 2014 13:22:30 +0100 De : Nicolaas Neuwahl Pour : Sebastien Labbe hi sébastien labbé, i'm the designer of the quantumino puzzle. i'm not a mathematician, i'm an architect. i like mathematics. i'm quite impressed to see the sage work on quantumino, also i have not the knowledge for full understanding. i have a question for you - can you tell me HOW MANY different quantumino- solutions exist? ty and bye nicolaas neuwahl

This summer was a good timing to launch the computation on my beautiful Intel® Core™ i5-4590 CPU @ 3.30GHz × 4 at Université de Liège. First, I improved the Sage code to allow a parallel computation of number of solutions in the dancing links code (#18987, merged in a Sage 6.9.beta6). Secondly, we may remark that each tiling of the \(2\times 5\times 8\) box can be rotated in order to find 3 other solutions. It is possible to gain a factor 4 by avoiding to count 4 times the same solution up to rotations (#19107, still needs work from myself). Thanks to Vincent Delecroix for doing the review on both ticket. Dividing the estimated 1024 days of computation needed by a factor \(4\times 4=16\) gives an approximation of 64 days to complete the computation. Two months, just enough to be tractable!

With those two tickets (some previous version to be honest) on top of sage-6.8, I started the computation on August 4th and the computation finished last week on September 18th for a total of 45 days. The computation was stopped only once on September 8th (I forgot to close firefox and thunderbird that night...).

The number of solutions and computation time for each pentamino put aside together with the first solution found is shown in the table below. We remark that some values are equal when the aside pentaminoes are miror images (why!?:).

634 900 493 solutions | 634 900 493 solutions |

2 days, 6:22:44.883358 | 2 days, 6:19:08.945691 |

509 560 697 solutions | 509 560 697 solutions |

2 days, 0:01:36.844612 | 2 days, 0:41:59.447773 |

628 384 422 solutions | 628 384 422 solutions |

2 days, 7:52:31.459247 | 2 days, 8:44:49.465672 |

1 212 362 145 solutions | 1 212 362 145 solutions |

3 days, 17:25:00.346627 | 3 days, 19:10:02.353063 |

197 325 298 solutions | 556 534 800 solutions |

22:51:54.439932 | 1 day, 19:05:23.908326 |

664 820 756 solutions | 468 206 736 solutions |

2 days, 8:48:54.767662 | 1 day, 20:14:56.014557 |

1 385 955 043 solutions | 1 385 955 043 solutions |

4 days, 1:40:30.270929 | 4 days, 4:44:05.399367 |

694 998 374 solutions | 694 998 374 solutions |

2 days, 11:44:29.631 | 2 days, 6:01:57.946708 |

1 347 221 708 solutions | |

3 days, 21:51:29.043459 |

Therefore the total number of solutions up to rotations is 13 366 431 646 which is indeed more than 10000:)

sage: L = [634900493, 634900493, 509560697, 509560697, 628384422, 628384422, 1212362145, 1212362145, 197325298, 556534800, 664820756, 468206736, 1385955043, 1385955043, 694998374, 694998374, 1347221708] sage: sum(L) 13366431646 sage: factor(_) 2 * 23 * 271 * 1072231

The machine (4 cores) | Intel® Core™ i5-4590 CPU @ 3.30GHz × 4 (Université de Liège) |

Computation Time | 45 days, (Aug 4th -- Sep 18th, 2015) |

Number of solutions (up to rotations) | 13 366 431 646 |

Number of solutions / cpu / second | 859 |

My code will be available on github.

**About the video on wikipedia.**

I must say that the video is not perfect. On wikipedia, the file talk page
of the video says that the *Jerky camera movement is distracting*. That is
because I managed to make the video out of images created by
`.show(viewer='tachyon')` which changes the coordinate system, hardcodes a
lot of parameters, zoom properly, simplifies stuff to make sure the user don't
see just a blank image. But, for making a movie, we need access to more
parameters especially the placement of the camera (to avoid the jerky
movement). I know that Tachyon allows all of that. It is still a project that I
have to create a more versatile `Graphics3D -> Tachyon` conversion allowing
to construct nice videos of evolving mathematical objects. That's another
story.

In a recent article with Valérie Berthé [BL15], we provided a multidimensional continued fraction algorithm called Arnoux-Rauzy-Poincaré (ARP) to construct, given any vector \(v\in\mathbb{R}_+^3\), an infinite word \(w\in\{1,2,3\}^\mathbb{N}\) over a three-letter alphabet such that the frequencies of letters in \(w\) exists and are equal to \(v\) and such that the number of factors (i.e. finite block of consecutive letters) of length \(n\) appearing in \(w\) is linear and less than \(\frac{5}{2}n+1\). We also conjecture that for almost all \(v\) the contructed word describes a discrete path in the positive octant staying at a bounded distance from the euclidean line of direction \(v\).

In Sage, you can construct this word using the next version of my package slabbe-0.2 (not released yet, email me to press me to finish it). The one with frequencies of letters proportionnal to \((1, e, \pi)\) is:

sage: from slabbe.mcf import algo sage: D = algo.arp.substitutions() sage: it = algo.arp.coding_iterator((1,e,pi)) sage: w = words.s_adic(it, repeat(1), D) word: 1232323123233231232332312323123232312323...

The factor complexity is close to 2n+1 and the balance is often less or equal to three:

sage: w[:10000].number_of_factors(100) 202 sage: w[:100000].number_of_factors(1000) 2002 sage: w[:1000].balance() 3 sage: w[:2000].balance() 3

Note that bounded distance from the euclidean line almost surely was proven in [DHS2013] for Brun algorithm, another MCF algorithm.

**Other approaches: Standard model and billiard sequences**

Other approaches have been proposed to construct such discrete lines.

One of them is the standard model of Eric Andres [A03]. It is also equivalent to billiard sequences in the cube. It is well known that the factor complexity of billiard sequences is quadratic \(p(n)=n^2+n+1\) [AMST94]. Experimentally, we can verify this. We first create a billiard word of some given direction:

sage: from slabbe import BilliardCube sage: v = vector(RR, (1, e, pi)) sage: b = BilliardCube(v) sage: b Cubic billiard of direction (1.00000000000000, 2.71828182845905, 3.14159265358979) sage: w = b.to_word() sage: w word: 3231232323123233213232321323231233232132...

We create some prefixes of \(w\) that we represent internally as `char*`.
The creation is slow because the implementation of billiard words in my
optional package is in Python and is not that efficient:

sage: p3 = Word(w[:10^3], alphabet=[1,2,3], datatype='char') sage: p4 = Word(w[:10^4], alphabet=[1,2,3], datatype='char') # takes 3s sage: p5 = Word(w[:10^5], alphabet=[1,2,3], datatype='char') # takes 32s sage: p6 = Word(w[:10^6], alphabet=[1,2,3], datatype='char') # takes 5min 20s

We see below that exactly \(n^2+n+1\) factors of length \(n<20\) appears in the prefix of length 1000000 of \(w\):

sage: A = ['n'] + range(30) sage: c3 = ['p_(w[:10^3])(n)'] + map(p3.number_of_factors, range(30)) sage: c4 = ['p_(w[:10^4])(n)'] + map(p4.number_of_factors, range(30)) sage: c5 = ['p_(w[:10^5])(n)'] + map(p5.number_of_factors, range(30)) # takes 4s sage: c6 = ['p_(w[:10^6])(n)'] + map(p6.number_of_factors, range(30)) # takes 49s sage: ref = ['n^2+n+1'] + [n^2+n+1 for n in range(30)] sage: T = table(columns=[A,c3,c4,c5,c6,ref]) sage: T n p_(w[:10^3])(n) p_(w[:10^4])(n) p_(w[:10^5])(n) p_(w[:10^6])(n) n^2+n+1 +----+-----------------+-----------------+-----------------+-----------------+---------+ 0 1 1 1 1 1 1 3 3 3 3 3 2 7 7 7 7 7 3 13 13 13 13 13 4 21 21 21 21 21 5 31 31 31 31 31 6 43 43 43 43 43 7 52 55 56 57 57 8 63 69 71 73 73 9 74 85 88 91 91 10 87 103 107 111 111 11 100 123 128 133 133 12 115 145 151 157 157 13 130 169 176 183 183 14 144 195 203 211 211 15 160 223 232 241 241 16 176 253 263 273 273 17 192 285 296 307 307 18 208 319 331 343 343 19 224 355 368 381 381 20 239 392 407 421 421 21 254 430 448 463 463 22 268 470 491 507 507 23 282 510 536 553 553 24 296 552 583 601 601 25 310 596 632 651 651 26 324 642 683 703 703 27 335 687 734 757 757 28 345 734 787 813 813 29 355 783 842 871 871

Billiard sequences generate paths that are at a bounded distance from an euclidean line. This is equivalent to say that the balance is finite. The balance is defined as the supremum value of difference of the number of apparition of a letter in two factors of the same length. For billiard sequences, the balance is 2:

sage: p3.balance() 2 sage: p4.balance() # takes 2min 37s 2

**Other approaches: Melançon and Reutenauer**

Melançon and Reutenauer [MR13] also suggested a method that generalizes Christoffel words in higher dimension. The construction is based on the application of two substitutions generalizing the construction of sturmian sequences. Below we compute the factor complexity and the balance of some of their words over a three-letter alphabet.

On a three-letter alphabet, the two morphisms are:

sage: L = WordMorphism('1->1,2->13,3->2') sage: R = WordMorphism('1->13,2->2,3->3') sage: L WordMorphism: 1->1, 2->13, 3->2 sage: R WordMorphism: 1->13, 2->2, 3->3

Example 1: periodic case \(LRLRLRLRLR\dots\). In this example, the factor complexity seems to be around \(p(n)=2.76n\) and the balance is at least 28:

sage: from itertools import repeat, cycle sage: W = words.s_adic(cycle((L,R)),repeat('1')) sage: W word: 1213122121313121312212212131221213131213... sage: map(W[:10000].number_of_factors, [10,20,40,80]) [27, 54, 110, 221] sage: [27/10., 54/20., 110/40., 221/80.] [2.70000000000000, 2.70000000000000, 2.75000000000000, 2.76250000000000] sage: W[:1000].balance() # takes 1.6s 21 sage: W[:2000].balance() # takes 6.4s 28

Example 2: \(RLR^2LR^4LR^8LR^{16}LR^{32}LR^{64}LR^{128}\dots\) taken from the conclusion of their article. In this example, the factor complexity seems to be \(p(n)=3n\) and balance at least as high (=bad) as \(122\):

sage: W = words.s_adic([R,L,R,R,L,R,R,R,R,L]+[R]*8+[L]+[R]*16+[L]+[R]*32+[L]+[R]*64+[L]+[R]*128,'1') sage: W.length() 330312 sage: map(W.number_of_factors, [10, 20, 100, 200, 300, 1000]) [29, 57, 295, 595, 895, 2981] sage: [29/10., 57/20., 295/100., 595/200., 895/300., 2981/1000.] [2.90000000000000, 2.85000000000000, 2.95000000000000, 2.97500000000000, 2.98333333333333, 2.98100000000000] sage: W[:1000].balance() # takes 1.6s 122 sage: W[:2000].balance() # takes 6s 122

Example 3: some random ones. The complexity \(p(n)/n\) occillates between 2 and 3 for factors of length \(n=1000\) in prefixes of length 100000:

sage: for _ in range(10): ....: W = words.s_adic([choice((L,R)) for _ in range(50)],'1') ....: print W[:100000].number_of_factors(1000)/1000. 2.02700000000000 2.23600000000000 2.74000000000000 2.21500000000000 2.78700000000000 2.52700000000000 2.85700000000000 2.33300000000000 2.65500000000000 2.51800000000000

For ten randomly generated words, the balance goes from 6 to 27 which is much more than what is obtained for billiard words or by our approach:

sage: for _ in range(10): ....: W = words.s_adic([choice((L,R)) for _ in range(50)],'1') ....: print W[:1000].balance(), W[:2000].balance() 12 15 8 24 14 14 5 11 17 17 14 14 6 6 19 27 9 16 12 12

[BL15] | V. Berthé, S. Labbé,
Factor Complexity of S-adic words generated by the Arnoux-Rauzy-Poincaré Algorithm,
Advances in Applied Mathematics 63 (2015) 90-130.
http://dx.doi.org/10.1016/j.aam.2014.11.001 |

[DHS2013] | Delecroix, Vincent, Tomás Hejda, and Wolfgang Steiner. “Balancedness of Arnoux-Rauzy and Brun Words.” In Combinatorics on Words, 119–31. Springer, 2013. http://link.springer.com/chapter/10.1007/978-3-642-40579-2_14. |

[A03] | E. Andres, Discrete linear objects in dimension n: the standard model, Graphical Models 65 (2003) 92-111. |

[AMST94] | P. Arnoux, C. Mauduit, I. Shiokawa, J. I. Tamura, Complexity of sequences defined by billiards in the cube, Bull. Soc. Math. France 122 (1994) 1-12. |

[MR13] | G. Melançon, C. Reutenauer, On a class of Lyndon words extending Christoffel words and related to a multidimensional continued fraction algorithm. J. Integer Seq. 16, No. 9, Article 13.9.7, 30 p., electronic only (2013). https://cs.uwaterloo.ca/journals/JIS/VOL16/Reutenauer/reut3.html |

The Oldenburger infinite sequence [O39]
\[
K = 1221121221221121122121121221121121221221\ldots
\]
also known under the name of Kolakoski, is equal to its *exponent
trajectory*. The exponent trajectory \(\Delta\) can be obtained by counting
the lengths of blocks of consecutive and equal letters:
\[
K =
1^12^21^22^11^12^21^12^21^22^11^22^21^12^11^22^11^12^21^22^11^22^11^12^21^12^21^22^11^12^21^12^11^22^11^22^21^12^21^2\ldots
\]
The sequence of exponents above gives the exponent trajectory of the
Oldenburger sequence:
\[
\Delta = 12211212212211211221211212\ldots
\]
which is equal to the original sequence \(K\).
You can define this sequence in Sage:

sage: K = words.KolakoskiWord() sage: K word: 1221121221221121122121121221121121221221... sage: K.delta() # delta returns the exponent trajectory word: 1221121221221121122121121221121121221221...

There are a lot of open problem related to basic properties of that sequence.
For example, we do not know if that sequence is recurrent, that is, all finite
subword or factor (finite block of consecutive letters) always reappear. Also,
it is still open to prove whether the density of `1` in that sequence is
equal to \(1/2\).

In this blog post, I do some computations on its abelian complexity \(p_{ab}(n)\) defined as the number of distinct abelian vectors of subwords of length \(n\) in the sequence. The abelian vector \(\vec{w}\) of a word \(w\) counts the number of occurences of each letter: \[ w = 12211212212 \quad \mapsto \quad 1^5 2^7 \text{, abelianized} \quad \mapsto \quad \vec{w} = (5, 7) \text{, the abelian vector of } w \]

Here are the abelian vectors of subwords of length 10 and 20 in the prefix of
length 100 of the Oldenburger sequence. The functions `abelian_vectors` and
`abelian_complexity` are not in Sage as of now. Code is available at trac
#17058 to be merged in Sage soon:

sage: prefix = words.KolakoskiWord()[:100] sage: prefix.abelian_vectors(10) {(4, 6), (5, 5), (6, 4)} sage: prefix.abelian_vectors(20) {(8, 12), (9, 11), (10, 10), (11, 9), (12, 8)}

Therefore, the prefix of length 100 has 3 vectors of subwords of length 10 and 5 vectors of subwords of length 20:

sage: p100.abelian_complexity(10) 3 sage: p100.abelian_complexity(20) 5

I import the `OldenburgerSequence` from my optional spkg because it is faster
than the implementation in Sage:

sage: from slabbe import KolakoskiWord as OldenburgerSequence sage: Olden = OldenburgerSequence()

I count the number of abelian vectors of subwords of length 100 in the prefix of length \(2^{20}\) of the Oldenburger sequence:

sage: prefix = Olden[:2^20] sage: %time prefix.abelian_vectors(100) CPU times: user 3.48 s, sys: 66.9 ms, total: 3.54 s Wall time: 3.56 s {(47, 53), (48, 52), (49, 51), (50, 50), (51, 49), (52, 48), (53, 47)}

Number of abelian vectors of subwords of length less than 100 in the prefix of length \(2^{20}\) of the Oldenburger sequence:

sage: %time L100 = map(prefix.abelian_complexity, range(100)) CPU times: user 3min 20s, sys: 1.08 s, total: 3min 21s Wall time: 3min 23s sage: from collections import Counter sage: Counter(L100) Counter({5: 26, 6: 26, 4: 17, 7: 15, 3: 8, 8: 4, 2: 3, 1: 1})

Let's draw that:

sage: labels = ('Length of factors', 'Number of abelian vectors') sage: title = 'Abelian Complexity of the prefix of length $2^{20}$ of Oldenburger sequence' sage: list_plot(L100, color='green', plotjoined=True, axes_labels=labels, title=title)

It seems to grow something like \(\log(n)\). Let's now consider subwords of length \(2^n\) for \(0\leq n\leq 12\) in the same prefix of length \(2^{20}\):

sage: %time L20 = [(2^n, prefix.abelian_complexity(2^n)) for n in range(20)] CPU times: user 41 s, sys: 239 ms, total: 41.2 s Wall time: 41.5 s sage: L20 [(1, 2), (2, 3), (4, 3), (8, 3), (16, 3), (32, 5), (64, 5), (128, 9), (256, 9), (512, 13), (1024, 17), (2048, 22), (4096, 27), (8192, 40), (16384, 46), (32768, 67), (65536, 81), (131072, 85), (262144, 90), (524288, 104)]

I now look at subwords of length \(2^n\) for \(0\leq n\leq 23\) in the longer prefix of length \(2^{24}\):

sage: prefix = Olden[:2^24] sage: %time L24 = [(2^n, prefix.abelian_complexity(2^n)) for n in range(24)] CPU times: user 20min 47s, sys: 13.5 s, total: 21min Wall time: 20min 13s sage: L24 [(1, 2), (2, 3), (4, 3), (8, 3), (16, 3), (32, 5), (64, 5), (128, 9), (256, 9), (512, 13), (1024, 17), (2048, 23), (4096, 33), (8192, 46), (16384, 58), (32768, 74), (65536, 98), (131072, 134), (262144, 165), (524288, 229), (1048576, 302), (2097152, 371), (4194304, 304), (8388608, 329)]

The next graph gather all of the above computations:

sage: G = Graphics() sage: legend = 'in the prefix of length 2^{}' sage: G += list_plot(L24, plotjoined=True, thickness=4, color='blue', legend_label=legend.format(24)) sage: G += list_plot(L20, plotjoined=True, thickness=4, color='red', legend_label=legend.format(20)) sage: G += list_plot(L100, plotjoined=True, thickness=4, color='green', legend_label=legend.format(20)) sage: labels = ('Length of factors', 'Number of abelian vectors') sage: title = 'Abelian complexity of Oldenburger sequence' sage: G.show(scale=('semilogx', 2), axes_labels=labels, title=title)

A linear growth in the above graphics with logarithmic \(x\) abcisse would mean a growth in \(\log(n)\). After those experimentations, my hypothesis is that the abelian complexity of the Oldenburger sequence grows like \(\log(n)^2\).

[O39] | Oldenburger, Rufus (1939). "Exponent trajectories in symbolic dynamics". Transactions of the American Mathematical Society 46: 453–466. doi:10.2307/1989933 |

These is a summary of the functionalities present in slabbe-0.1 optional Sage package. It depends on version 6.3 of Sage because it uses RecursivelyEnumeratedSet code that was merged in 6.3. It contains modules on digital geometry, combinatorics on words and more.

Install the optional spkg (depends on sage-6.3):

sage -i http://www.liafa.univ-paris-diderot.fr/~labbe/Sage/slabbe-0.1.spkg

In each of the example below, you first have to import the module once and for all:

sage: from slabbe import *

To construct the image below, make sure to use tikz package so that `view` is
able to compile tikz code when called:

sage: latex.add_to_preamble("\\usepackage{tikz}") sage: latex.extra_preamble() '\\usepackage{tikz}'

sage: p = DiscretePlane([1,pi,7], 1+pi+7, mu=0) sage: d = DiscreteTube([-5,5],[-5,5]) sage: I = p & d sage: I Intersection of the following objects: Set of points x in ZZ^3 satisfying: 0 <= (1, pi, 7) . x + 0 < pi + 8 DiscreteTube: Preimage of [-5, 5] x [-5, 5] by a 2 by 3 matrix sage: clip = d.clip() sage: tikz = I.tikz(clip=clip) sage: view(tikz, tightpage=True)

sage: L = DiscreteLine([-2,3], 5) sage: b = DiscreteBox([0,10], [0,10]) sage: I = L & b sage: I Intersection of the following objects: Set of points x in ZZ^2 satisfying: 0 <= (-2, 3) . x + 0 < 5 [0, 10] x [0, 10] sage: I.plot()

This module was developped for the article on the combinatorial properties of double square tiles written with Ariane Garon and Alexandre Blondin Massé [BGL2012]. The original version of the code was written with Alexandre.

sage: D = DoubleSquare((34,21,34,21)) sage: D Double Square Tile w0 = 3032321232303010303230301012101030 w4 = 1210103010121232121012123230323212 w1 = 323030103032321232303 w5 = 101212321210103010121 w2 = 2321210121232303232123230301030323 w6 = 0103032303010121010301012123212101 w3 = 212323032321210121232 w7 = 030101210103032303010 (|w0|, |w1|, |w2|, |w3|) = (34, 21, 34, 21) (d0, d1, d2, d3) = (42, 68, 42, 68) (n0, n1, n2, n3) = (0, 0, 0, 0) sage: D.plot()

sage: D.extend(0).extend(1).plot()

We have shown that using two invertible operations (called SWAP and TRIM), every double square tiles can be reduced to the unit square:

sage: D.plot_reduction()

The reduction operations are:

sage: D.reduction() ['SWAP_1', 'TRIM_1', 'TRIM_3', 'SWAP_1', 'TRIM_1', 'TRIM_3', 'TRIM_0', 'TRIM_2']

The result of the reduction is the unit square:

sage: unit_square = D.apply(D.reduction()) sage: unit_square Double Square Tile w0 = w4 = w1 = 3 w5 = 1 w2 = w6 = w3 = 2 w7 = 0 (|w0|, |w1|, |w2|, |w3|) = (0, 1, 0, 1) (d0, d1, d2, d3) = (2, 0, 2, 0) (n0, n1, n2, n3) = (0, NaN, 0, NaN) sage: unit_square.plot()

Since SWAP and TRIM are invertible operations, we can recover every double square from the unit square:

sage: E = unit_square.extend(2).extend(0).extend(3).extend(1).swap(1).extend(3).extend(1).swap(1) sage: D == E True

This module was developped for the article on a d-dimensional extension of Christoffel Words written with Christophe Reutenauer [LR2014].

sage: G = ChristoffelGraph((6,10,15)) sage: G Christoffel set of edges for normal vector v=(6, 10, 15) sage: tikz = G.tikz_kernel() sage: view(tikz, tightpage=True)

This module was developped for the article on the factor complexity of infinite sequences genereated by substitutions written with Valérie Berthé [BL2014].

The extension type of an ordinary bispecial factor:

sage: L = [(1,3), (2,3), (3,1), (3,2), (3,3)] sage: E = ExtensionType1to1(L, alphabet=(1,2,3)) sage: E E(w) 1 2 3 1 X 2 X 3 X X X m(w)=0, ordinary sage: E.is_ordinaire() True

Creation of a strong-weak pair of bispecial words from a neutral
**not ordinaire** word:

sage: p23 = WordMorphism({1:[1,2,3],2:[2,3],3:[3]}) sage: e = ExtensionType1to1([(1,2),(2,3),(3,1),(3,2),(3,3)], [1,2,3]) sage: e E(w) 1 2 3 1 X 2 X 3 X X X m(w)=0, not ord. sage: A,B = e.apply(p23) sage: A E(3w) 1 2 3 1 2 X X 3 X X X m(w)=1, not ord. sage: B E(23w) 1 2 3 1 X 2 3 X m(w)=-1, not ord.

This module was written for fun. It uses cython implementation inspired from the 10 lines of C code written by Dominique Bernardi and shared during Sage Days 28 in Orsay, France, in January 2011.

sage: K = KolakoskiWord() sage: K word: 1221121221221121122121121221121121221221... sage: %time K[10^5] CPU times: user 1.56 ms, sys: 7 µs, total: 1.57 ms Wall time: 1.57 ms 1 sage: %time K[10^6] CPU times: user 15.8 ms, sys: 30 µs, total: 15.8 ms Wall time: 15.9 ms 2 sage: %time K[10^8] CPU times: user 1.58 s, sys: 2.28 ms, total: 1.58 s Wall time: 1.59 s 1 sage: %time K[10^9] CPU times: user 15.8 s, sys: 12.4 ms, total: 15.9 s Wall time: 15.9 s 1

This is much faster than the Python implementation available in Sage:

sage: K = words.KolakoskiWord() sage: %time K[10^5] CPU times: user 779 ms, sys: 25.9 ms, total: 805 ms Wall time: 802 ms 1

[BGL2012] | A. Blondin Massé, A. Garon, S. Labbé, Combinatorial properties
of double square tiles, Theoretical Computer Science 502 (2013) 98-117.
doi:10.1016/j.tcs.2012.10.040 |

[LR2014] | Labbé, Sébastien, and Christophe Reutenauer. A d-dimensional Extension of Christoffel Words. arXiv:1404.4021 (April 15, 2014). |

[BL2014] | V. Berthé, S. Labbé, Factor Complexity of S-adic sequences generated by the Arnoux-Rauzy-Poincaré Algorithm. arXiv:1404.4189 (April, 2014). |

Since two years I wrote thousands of line of private code for my own research. Each module having between 500 and 2000 lines of code. The code which is the more clean corresponds to code written in conjunction with research articles. People who know me know that I systematically put docstrings and doctests in my code to facilitate reuse of the code by myself, but also in the idea of sharing it and eventually making it public.

I did not made that code into Sage because it was not mature enough. Also, when I tried to make a complete module go into Sage (see #13069 and #13346), then the monstrous never evolving #12224 became a dependency of the first and the second was unofficially reviewed asking me to split it into smaller chunks to make the review process easier. I never did it because I spent already too much time on it (making a module 100% doctested takes time). Also, the module was corresponding to a published article and I wanted to leave it just like that.

**Getting new modules into Sage is hard**

In general, the introduction of a complete new module into Sage is hard especially for beginners. Here are two examples I feel responsible for: #10519 is 4 years old and counting, the author has a new work and responsabilities; in #12996, the author was decouraged by the amount of work given by the reviewers. There is a lot of things a beginner has to consider to obtain a positive review. And even for a more advanced developper, other difficulties arise. Indeed, a module introduces a lot of new functions and it may also introduce a lot of new bugs... and Sage developpers are sometimes reluctant to give it a positive review. And if it finally gets a positive review, it is not available easily to normal users of Sage until the next release of Sage.

**Releasing my own Sage package**

Still I felt the need around me to make my code public. But how? There are people (a few of course but I know there are) who are interested in reproducing computations and images done in my articles. This is why I came to the idea of releasing my own Sage package containing my public research code. This way both developpers and colleagues that are user of Sage but not developpers will be able to install and use my code. This will make people more aware if there is something useful in a module for them. And if one day, somebody tells me: "this should be in Sage", then I will be able to say : "I agree! Do you want to review it?".

**Old style Sage package** vs **New sytle git Sage package**

Then I had to chose between the old and the new style for Sage packages. I did not like the new style, because

- I wanted the history of my package to be independant of the history of Sage,
- I wanted it to be as easy to install as
sage -i slabbe,- I wanted it to work on any recent enough version of Sage,
- I wanted to be able to release a new version, give it to a colleague who could install it right away without changing its own Sage (i.e., updating the checksums).

Therefore, I choose the old style. I based my work on other optional Sage packages, namely the SageManifolds spkg and the ore_algebra spkg.

**Content of the initial version**

The initial version of the slabbe Sage package has modules concerning four
topics: *Digital geometry*, *Combinatorics on words*, *Combinatorics* and
*Python class inheritance*.

For installation or for release notes of the initial version of the spkg, consult the slabbe spkg section of the Sage page of this website.

]]>At Sage Days 57, I worked on the trac ticket #6637: *standardize the
interface to TransitiveIdeal and friends*. My patch proposes to replace
`TransitiveIdeal` and `SearchForest` by a new class called
`RecursivelyEnumeratedSet` that would handle every case.

A set S is called recursively enumerable if there is an algorithm that
enumerates the members of S. We consider here the recursively enumerated
set that are described by some `seeds` and a successor function `succ`.
The successor function may have some structure (symmetric, graded, forest)
or not. Many kinds of iterators are provided: depth first search, breadth
first search or elements of given depth.

Consider the permutations of \(\{1,2,3\}\) and the poset generated by the
method `permutohedron_succ`:

sage: P = Permutations(3) sage: d = {p:p.permutohedron_succ() for p in P} sage: S = Poset(d) sage: S.plot()

The `TransitiveIdeal` allows to generates all permutations from the identity
permutation using the method `permutohedron_succ` as successor function:

sage: succ = attrcall("permutohedron_succ") sage: seed = [Permutation([1,2,3])] sage: T = TransitiveIdeal(succ, seed) sage: list(T) [[1, 2, 3], [2, 1, 3], [1, 3, 2], [2, 3, 1], [3, 2, 1], [3, 1, 2]]

Remark that the previous ordering is neither breadth first neither depth first. It is a naive search because it stores the element to process in a set instead of a queue or a stack.

Note that the method `permutohedron_succ` produces a graded poset. Therefore,
one may use the `TransitiveIdealGraded` class instead:

sage: T = TransitiveIdealGraded(succ, seed) sage: list(T) [[1, 2, 3], [2, 1, 3], [1, 3, 2], [2, 3, 1], [3, 1, 2], [3, 2, 1]]

For `TransitiveIdealGraded`, the enumeration is breadth first search.
Althougth, if you look at the code (version Sage 6.1.1 or earlier), we see that
this iterator do not make use of the graded hypothesis at all because the
`known` set remembers every generated elements:

current_level = self._generators known = set(current_level) depth = 0 while len(current_level) > 0 and depth <= self._max_depth: next_level = set() for x in current_level: yield x for y in self._succ(x): if y == None or y in known: continue next_level.add(y) known.add(y) current_level = next_level depth += 1 return

sage: succ = attrcall("permutohedron_succ") sage: seed = [Permutation([1..5])] sage: T = TransitiveIdeal(succ, seed) sage: %time L = list(T) CPU times: user 26.6 ms, sys: 1.57 ms, total: 28.2 ms Wall time: 28.5 ms

sage: seed = [Permutation([1..8])] sage: T = TransitiveIdeal(succ, seed) sage: %time L = list(T) CPU times: user 14.4 s, sys: 141 ms, total: 14.5 s Wall time: 14.8 s

sage: seed = [Permutation([1..5])] sage: T = TransitiveIdealGraded(succ, seed) sage: %time L = list(T) CPU times: user 25.3 ms, sys: 1.04 ms, total: 26.4 ms Wall time: 27.4 ms

sage: seed = [Permutation([1..8])] sage: T = TransitiveIdealGraded(succ, seed) sage: %time L = list(T) CPU times: user 14.5 s, sys: 85.8 ms, total: 14.5 s Wall time: 14.7 s

In conlusion, use `TransitiveIdeal` for naive search algorithm and use
`TransitiveIdealGraded` for breadth search algorithm. Both class do not use
the graded hypothesis.

The new class `RecursivelyEnumeratedSet` provides all iterators for each
case. The example below are for the graded case.

Depth first search iterator:

sage: succ = attrcall("permutohedron_succ") sage: seed = [Permutation([1..5])] sage: R = RecursivelyEnumeratedSet(seed, succ, structure='graded') sage: it_depth = R.depth_first_search_iterator() sage: [next(it_depth) for _ in range(5)] [[1, 2, 3, 4, 5], [1, 2, 3, 5, 4], [1, 2, 5, 3, 4], [1, 2, 5, 4, 3], [1, 5, 2, 4, 3]]

Breadth first search iterator:

sage: it_breadth = R.breadth_first_search_iterator() sage: [next(it_breadth) for _ in range(5)] [[1, 2, 3, 4, 5], [1, 3, 2, 4, 5], [1, 2, 4, 3, 5], [2, 1, 3, 4, 5], [1, 2, 3, 5, 4]]

Elements of given depth iterator:

sage: list(R.elements_of_depth_iterator(9)) [[5, 4, 2, 3, 1], [4, 5, 3, 2, 1], [5, 3, 4, 2, 1], [5, 4, 3, 1, 2]] sage: list(R.elements_of_depth_iterator(10)) [[5, 4, 3, 2, 1]]

Levels (a level is a set of elements of the same depth):

sage: R.level(0) [[1, 2, 3, 4, 5]] sage: R.level(1) {[1, 2, 3, 5, 4], [1, 2, 4, 3, 5], [1, 3, 2, 4, 5], [2, 1, 3, 4, 5]} sage: R.level(2) {[1, 2, 4, 5, 3], [1, 2, 5, 3, 4], [1, 3, 2, 5, 4], [1, 3, 4, 2, 5], [1, 4, 2, 3, 5], [2, 1, 3, 5, 4], [2, 1, 4, 3, 5], [2, 3, 1, 4, 5], [3, 1, 2, 4, 5]} sage: R.level(3) {[1, 2, 5, 4, 3], [1, 3, 4, 5, 2], [1, 3, 5, 2, 4], [1, 4, 2, 5, 3], [1, 4, 3, 2, 5], [1, 5, 2, 3, 4], [2, 1, 4, 5, 3], [2, 1, 5, 3, 4], [2, 3, 1, 5, 4], [2, 3, 4, 1, 5], [2, 4, 1, 3, 5], [3, 1, 2, 5, 4], [3, 1, 4, 2, 5], [3, 2, 1, 4, 5], [4, 1, 2, 3, 5]} sage: R.level(9) {[4, 5, 3, 2, 1], [5, 3, 4, 2, 1], [5, 4, 2, 3, 1], [5, 4, 3, 1, 2]} sage: R.level(10) {[5, 4, 3, 2, 1]}

We construct a recursively enumerated set with symmetric structure and depth first search for default enumeration algorithm:

sage: succ = lambda a: [(a[0]-1,a[1]), (a[0],a[1]-1), (a[0]+1,a[1]), (a[0],a[1]+1)] sage: seeds = [(0,0)] sage: C = RecursivelyEnumeratedSet(seeds, succ, structure='symmetric', algorithm='depth') sage: C A recursively enumerated set with a symmetric structure (depth first search)

In this case, depth first search is the default algorithm for iteration:

sage: it_depth = iter(C) sage: [next(it_depth) for _ in range(10)] [(0, 0), (0, 1), (0, 2), (0, 3), (0, 4), (0, 5), (0, 6), (0, 7), (0, 8), (0, 9)]

Breadth first search. This algorithm makes use of the symmetric structure and remembers only the last two levels:

sage: it_breadth = C.breadth_first_search_iterator() sage: [next(it_breadth) for _ in range(10)] [(0, 0), (0, 1), (0, -1), (1, 0), (-1, 0), (-1, 1), (-2, 0), (0, 2), (2, 0), (-1, -1)]

Levels (elements of given depth):

sage: sorted(C.level(0)) [(0, 0)] sage: sorted(C.level(1)) [(-1, 0), (0, -1), (0, 1), (1, 0)] sage: sorted(C.level(2)) [(-2, 0), (-1, -1), (-1, 1), (0, -2), (0, 2), (1, -1), (1, 1), (2, 0)]

We get same timings as for `TransitiveIdeal` but it uses less memory so it
might be able to enumerate bigger sets:

sage: succ = attrcall("permutohedron_succ") sage: seed = [Permutation([1..5])] sage: R = RecursivelyEnumeratedSet(seed, succ, structure='graded') sage: %time L = list(R) CPU times: user 24.7 ms, sys: 1.33 ms, total: 26.1 ms Wall time: 26.4 ms

sage: seed = [Permutation([1..8])] sage: R = RecursivelyEnumeratedSet(seed, succ, structure='graded') sage: %time L = list(R) CPU times: user 14.5 s, sys: 70.2 ms, total: 14.5 s Wall time: 14.6 s

Today I am presenting the IPython notebook at the meeting of the Sage Paris group. This post gathers what I prepared.

First you can install the ipython notebook in Sage as explained in this previous blog post. If everything works, then you run:

sage -ipython notebook

and this will open a browser.

Create a new notebook and type:

In [1]: 3 + 3 6 In [2]: 2 / 3 0 In [3]: matrix Traceback (most recent call last): ... NameError: name 'matrix' is not defined

By default, Sage preparsing is turn off and Sage commands are not known. To turn on the Sage preparsing (thanks to a post of Jason on sage-devel):

%load_ext sage.misc.sage_extension

Since sage-6.2, according to sage-devel, the command is:

%load_ext sage

You now get Sage commands working in ipython:

In [4]: 3 + 4 Out[4]: 7 In [5]: 2 / 3 Out[5]: 2/3 In [6]: type(_) Out[6]: <type 'sage.rings.rational.Rational'> In [7]: matrix(3, range(9)) Out[7]: [0 1 2] [3 4 5] [6 7 8]

If the output is too big, click on **Out** to scroll
or hide the output:

In [8]: range(1000)

3D graphics works but open in a new Jmol window:

In [9]: sphere()

Similarly, 2D graphics works but open in a new window:

In [10]: plot(sin(x), (x,0,10))

To create inline matplotlib graphics, the notebook must be started with this command:

sage -ipython notebook --pylab=inline

Then, a matplotlib plot can be drawn inline (example taken from this notebook):

import matplotlib.pyplot as plt import numpy as np x = np.linspace(0, 3*np.pi, 500) plt.plot(x, np.sin(x**2)) plt.title('A simple chirp');

Or with:

%load http://matplotlib.org/mpl_examples/showcase/integral_demo.py

According to the previous cited notebook, it seems, that the inline mode can also be decided from the notebook using a magic command, but with my version of ipython (0.13.2), I get an error:

In [11]: %matplotlib inline ERROR: Line magic function `%matplotlib` not found.

Change an input cell into a markdown cell and then you may use latex:

Test $\alpha+\beta+\gamma$

The output can be shown with latex and mathjax using the ipython display function:

from IPython.display import display, Math def my_show(obj): return display(Math(latex(obj))) y = 1 / (x^2+1) my_show(y)

Create a new notebook with only one cell. Name it `range_10`
and save:

In [1]: range(10) Out[1]: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

The file `range_10.ipynb` is saved in the directory. You can also download it
from File > Download as > IPython (.ipynb). Here is the content of the file
`range_10.ipynb`:

{ "metadata": { "name": "range_10" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "code", "collapsed": false, "input": [ "range(10)" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "pyout", "prompt_number": 1, "text": [ "[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]" ] } ], "prompt_number": 1 }, { "cell_type": "code", "collapsed": false, "input": [], "language": "python", "metadata": {}, "outputs": [] } ], "metadata": {} } ] }

A ipynb file is written in json format. Below, we
use json to open the file ``range_10.ipynb` as a Python dictionnary.

sage: s = open('range_10.ipynb','r').read() sage: import json sage: D = json.loads(s) sage: type(D) dict sage: D.keys() [u'nbformat', u'nbformat_minor', u'worksheets', u'metadata'] sage: D {u'metadata': {u'name': u'range_10'}, u'nbformat': 3, u'nbformat_minor': 0, u'worksheets': [{u'cells': [{u'cell_type': u'code', u'collapsed': False, u'input': [u'range(10)'], u'language': u'python', u'metadata': {}, u'outputs': [{u'output_type': u'pyout', u'prompt_number': 1, u'text': [u'[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]']}], u'prompt_number': 1}, {u'cell_type': u'code', u'collapsed': False, u'input': [], u'language': u'python', u'metadata': {}, u'outputs': []}], u'metadata': {}}]}

Download the file `vaucanson.ipynb` from the last meeting of Paris Sage
Users. You can view the complete demo including pictures of automaton even if
you are not able to install vaucanson on your machine.

In a Python file, separate your code with the following line to create cells:

# <codecell>

For example, create the following Python file. Then, import it in the notebook. It will get translated to ipynb format automatically.

# -*- coding: utf-8 -*- # <nbformat>3.0</nbformat> # <codecell> %load_ext sage.misc.sage_extension # <codecell> matrix(4, range(16)) # <codecell> factor(2^40-1)

Since release 1.0 of IPython, many conversion from ipynb to other format are possible (html, latex, slides, markdown, rst, python). Unfortunately, the version of IPython in Sage is still 0.13.2 as of today but the version 1.2.1 will be in sage-6.2.

Aujourd'hui avait lieu une rencontre de l'ANR DynA3S. Suite à une présentation de Brigitte Vallée, j'ai codé quelques lignes en Sage pour étudier une fonction qu'elle a introduite. Cette fonction est reliée à la compréhension de la densité des termes sous-diagonaux dans l'exécution de l'algorithme LLL.

D'abord voici mon fichier: brigitte.sage.

Pour utiliser ce fichier, il faut d'abord l'importer dans Sage en utilisant la
commande suivante. En ligne de commande, ça fonctionne bien. Dans le Sage
notebook, je ne sais plus trop si la commande `load` permet encore de le
faire (?):

sage: %runfile brigitte.sage # not tested

On doit générer plusieurs orbites pour visualiser quelque chose, car les orbites de la fonction sont de taille 1, 2 ou 3 en général avant que la condition d'arrêt soit atteinte. Ici, on génère 10000 orbites (les points initiaux sont choisis aléatoirement et uniformément dans \([0,1]\times[-0.5, 0.5]\). On dessine les derniers points des orbites:

sage: D = plusieurs_orbit(10000) Note: la plus longue orbite est de taille 3 sage: A = points(D[0], color='red', legend_label='derniers') sage: B = points(D[1], color='blue', legend_label='avant derniers') sage: C = points(D[2], color='black', legend_label='2e avant derniers') sage: G = A + B + C sage: G.axes_labels(("$x$", r"$\nu$")) sage: title = r"$(x,\nu) \mapsto (\frac{x}{(x+\nu^2)^2},\frac{\nu}{(x+\nu^2)})$" sage: G.show(title=title, xmax=2)

Un raccourci pour faire à peu près le même dessin que ci-haut:

sage: draw_plusieurs_orbites(10000).show(xmax=2)

On dessine des histogrammes surperposés de la densité de ces points une fois projetés sur l'axe des \(\nu\):

sage: histogrammes_nu(10000, nbox=10)

Le dessin semble indiquer que la densité non uniforme semble provenir simplement par les points \((x,\nu)\) tels que \(x\leq 1\).

On dessine des histogrammes superposés de la densité de ces points une fois projetés sur l'axe des \(x\) (on donne des couleurs selon la valeur de \(\nu\)):

sage: histogrammes_x(30000, nbox=5, ymax=1500, xmax=8)

Le dessin semble indiquer que la densité ne dépend pas de \(\nu\) pour \(x\geq 1\).

]]>(NEW: See also the demo I made at the Sage Paris group meeting in March 2014.)

Ticket #12719 (Upgrade to IPython 0.13) was merged into sage-5.7.beta1. This took a lot of energy (see the number of comments in the ticket and especially the number of patches and dependencies). Big thanks to Volker Braun, Mike Hansen, Jason Grout, Jeroen Demeyer who worked on this since almost one year. Note that in December 2012, the IPython project has received a $1.15M grant from the Alfred P. Sloan foundation, that will support IPython development for the next two years. I really like this IPython sage command line interface so it is really good news!

**The IPython notebook**

Since version 0.12 (December 21 2011), IPython is released with its own notebook. The differences with the Sage Notebook are explained by Fernando Perez, leader of IPython project, in the blog post The IPython notebook: a historical retrospective he wrote in January 2012. One of the differences is that the IPython Notebook run in its own directory whereas each cell of the Sage Notebook lives in its directory. As William Stein says in the presentation Browser-based notebook interfaces for mathematical software - past, present and future he gave last December at ICERM, there are plenty of projects and directions these days for those interfaces.

In May 2012, I tested the same ticket which was to upgrade to IPython 0.12 at that time. Today, I was curious to test it again.

First, I installed sage-5.7.beta4:

./sage -version Sage Version 5.7.beta4, Release Date: 2013-02-09

Install tornado:

./sage -sh easy_install-2.7 tornado

[update March 6th, 2014] Note that some linux user have to install
`libssl-dev` before tornado:

sudo apt-get install libssl-dev

Install zeromq and pyzmq:

./sage -i zeromq ./sage -i pyzmq

Start the ipython notebook:

./sage -ipython notebook [NotebookApp] Using existing profile dir: u'/Users/slabbe/.sage/ipython-0.12/profile_default' [NotebookApp] Serving notebooks from /Users/slabbe/Applications/sage-5.7.beta4 [NotebookApp] The IPython Notebook is running at: http://127.0.0.1:8888/ [NotebookApp] Use Control-C to stop this server and shut down all kernels.

Create a new notebook. One may use sage commands by adding the line `from
sage.all import *` in the first cell.

The next things I want to look at are:

]]>

- Test the conversion of files from
.pyto.pynb.- Test the conversion of files from
.rstto.pynb.- Test the qtconsole.
- Test the parallel computing capacities of the IPython.

Since Sage Days 20 at Marseille held in January 2010, I have been doing the same example over and over again each time I showed someone else how object oriented coding works in Python: using fruits, strawberry, oranges and bananas.

Here is my file: fruit.py. I use to build it from scratch by adding one line at a time using attach command to see what has changed starting with Banana class, then Strawberry class then Fruit class which gathers all common methods.

This time, I wrote the complete documentation (all tests pass, coverage is 100%) and followed Sage coding convention as far as I know them. Thus, I hope this file can be useful as an example to explain those coding convention to newcomers.

One may check that all tests pass using:

$ sage -t fruit.py sage -t "fruit.py" [3.7 s] ---------------------------------------------------------------------- All tests passed! Total time for all tests: 3.8 seconds

One may check that documentation and doctest coverage is 100%:

$ sage -coverage fruit.py ---------------------------------------------------------------------- fruit.py SCORE fruit.py: 100% (10 of 10) ----------------------------------------------------------------------

This message is about differences between a **Python function** and a
**symbolic function**. This is also explained in the Some Common Issues with
Functions page in the Sage Tutorial.

In Sage, one may define a symbolic function like:

sage: f(x) = x^2-1

And draw it using one the following way (both works):

sage: plot(f, (x,-10,10)) sage: plot(f(x), (x,-10,10))

Here both `f` and `f(x)` are symbolic expressions:

sage: type(f) <type 'sage.symbolic.expression.Expression'> sage: type(f(x)) <type 'sage.symbolic.expression.Expression'>

although there are different:

sage: f x |--> x^2 - 1 sage: f(x) x^2 - 1

Now if `f` is a *Python* function defined with a `def` statement:

sage: def f(x): ....: if x>0: ....: return x ....: else: ....: return 0

It is really a Python function:

sage: f <function f at 0xb933470> sage: type(f) <type 'function'>

As above, one can draw the function `f`:

sage: plot(f, (x,-10,10))

But be carefull, drawing `f(x)` will not work as expected:

sage: plot(f(x), (x,-10,10))

Why? Because, the python function `f` gets evaluated on the variable `x`
and this may either raise an exception depending on the definition of `f` or
return some result which might not be a symbolic expression. Here `f(x)` gets
always evaluated to zero because in the definition of `f`, `bool(x > 0)`
returns `False`:

sage: x x sage: bool(x > 0) False sage: f(x) 0

Hence the following constant function is drawn:

sage: plot(0, (x,-10,10))

which is not what we want.

]]>Today, I am presenting the Chapter 3 of the book Probability on Graphs of
Geoffrey Grimmett during a monthly reading seminar at LIAFA. The title of
the chapter is *Percolation and self-avoiding walks*. I did some computations
to improve my intuition on the question. My code is in the following file :
bond_percolation.sage. This post is about some of my computations. You
might want to test them yourself online using the Sage Cell Server.

Let \(\mathbb{L}^d=(\mathbb{Z}^d,\mathbb{E}^d)\) be the hypercubic
lattice. Let \(p\in[0,1]\). Each edge \(e\in \mathbb{E}^d\) is
designated either *open* with probability \(p\), or *closed* otherwise,
different edges receiving independant states. For \(x,y\in \mathbb{Z}^d\),
we write \(x \leftrightarrow y \) if there exists an open path joining
\(x\) and \(y\). For \(x\in \mathbb{Z}^d\), we consider the open
cluster \(C_x\) containing \(x\) :
\[
C_x = \{y \in \mathbb{Z}^d : x \leftrightarrow y \}.
\]
The percolation probability \(\Theta(p)\) is given by
\[
\Theta(p) = P_p(\vert C_0\vert=\infty).
\]
Finally, the critical probability is defined as
\[
p_c = \sup\{p : \Theta(p) = 0 \}.
\]
The question is to compute \(p_c\). Results in the Chapter give lower bound
and upper bound for \(p_c\). Many problems are still open like the one
claiming that \(\Theta(p_c) = 0\) for all \(d\geq 2\): it is known only
for \(d=2\) and \(d\geq 19\) according to a remark in the chapter.

A bond percolation sample inside the box \(\Lambda(m)=[-m,m]^d\) when \(p=0.5\) and \(d=2\):

sage: S = BondPercolationSample(p=0.5, d=2) sage: S.plot(m=40, pointsize=10, thickness=1) Graphics object consisting of 7993 graphics primitives sage: _.show()

Another time gives something different:

sage: S = BondPercolationSample(p=0.5, d=2) sage: S.plot(m=40, pointsize=10, thickness=1) Graphics object consisting of 10176 graphics primitives sage: _.show()

From `p=0.1` to `p=0.9`:

sage: percolation_graphics_array(srange(0.1,1,0.1), d=2, m=5)

From `p=0.41` to `p=0.49`:

sage: percolation_graphics_array(srange(0.41,0.50,0.01), d=2, m=5)

From `p=0.51` to `p=0.59`:

sage: percolation_graphics_array(srange(0.51,0.60,0.01), d=2, m=5)

In every case, we have the following upper bound for the percolation probability: \[ \Theta(p) = \mathbb{P}_p(\vert C_0\vert=\infty) \leq \mathbb{P}_p(\vert C_0\vert > 1) = 1 - \mathbb{P}_p(\vert C_0\vert = 1) = 1 - (1-p)^{2d}. \] In particular, if \(p\neq 1\), then \(\Theta(p)<1\). In Sage, define the upper bound:

sage: p,n = var('p,n') sage: d = var('d') sage: upper_bound = 1 - (1-p)^(2*d)

Also, from Equation (3.8), we have the following lower bound: \[ \Theta(p) \geq 1 - \sum_{n=4}^{\infty} n (4(1-p))^n. \]

In Sage, define the lower bound:

sage: p,n = var('p,n') sage: lower_bound = 1 - sum(n*(4*(1-p))^n,n,4,oo) sage: lower_bound.factor() -(3072*p^5 - 14336*p^4 + 26624*p^3 - 24592*p^2 + 11288*p - 2057)/(4*p - 3)^2

This is not defined when \(p=3/4\), but we are interested in the values in the interval \(]3/4,1]\). In particular, for which value of \(p\) is this lower bound strictly larger than zero:

sage: root = lower_bound.find_root(0.76, 0.99); root 0.8639366490304586

Let's now draw a graph of the lower and upper bound:

sage: U = plot(upper_bound(d=2),(0,1),color='red', thickness=3) sage: L = plot(lower_bound,(0.86,1),color='green', thickness=3) sage: G = U + L sage: G += point((root, 0), color='red', size=20) sage: lower = r"$1-\sum_{n=4}^{\infty} n4^n(1-p)^n$" sage: upper = r"$1 -(1-p)^{4}$" sage: title = r"$1-\sum_{n=4}^{\infty} n4^n(1-p)^n\leq\Theta(p)\leq 1 -(1-p)^{2d}$" sage: G += text(title, (.5, 1.05), color='black', fontsize=15) sage: G += text(upper, (.3, 0.5), color='red', fontsize=20) sage: G += text(lower, (.7, 0.5), color='green', fontsize=20) sage: G += text("%.5f"%root,(0.88, .03), color='green', horizontal_alignment='left') sage: G.show()

Thus we conclude that \(\Theta(p) >0\) for \(p>0.8639\) and thus \(p_c \leq 0.8639\).

The code allows to define the percolation probability function for a given
dimension `d`. It generates `n` samples and consider the cluster to be
infinite if its cardinality is larger than the given `stop` value.

Here we use Sage adaptative recursion algorithm for drawing the plot of the
percolation probability which finds the particular important intervals to ask
for more values of the function. See help section of plot function for details.
Because `T` might be long to compute we start with only 4 points.

When `stop=100`:

sage: T = PercolationProbability(d=2, n=10, stop=100) sage: T.return_plot((0,1),adaptive_recursion=4,plot_points=4).show()

When `stop=1000`:

sage: T = PercolationProbability(d=2, n=10, stop=1000) sage: T.return_plot((0,1),adaptive_recursion=4,plot_points=4).show()

When `stop=2000`:

sage: T = PercolationProbability(d=2, n=10, stop=2000) sage: T.return_plot((0,1),adaptive_recursion=4,plot_points=4).show()

When `stop=100`:

sage: T = PercolationProbability(d=3, n=10, stop=100) sage: T.return_plot((0,1),adaptive_recursion=4,plot_points=4).show()

When `stop=1000`:

sage: T = PercolationProbability(d=3, n=10, stop=1000) sage: T.return_plot((0,1),adaptive_recursion=4,plot_points=4).show()

When `stop=100`:

sage: T = PercolationProbability(d=4, n=10, stop=100) sage: T.return_plot((0,1),adaptive_recursion=4,plot_points=4).show()

When `stop=100`:

sage: T = PercolationProbability(d=13, n=10, stop=100) sage: T.return_plot((0,1),adaptive_recursion=4,plot_points=4).show()

Theorem 3.2 states that \(0 < p_c < 1\), but its proof does much more in fact. Following the computation we just did for Equation (3.8), we get for \(d=2\) \[ 0.3333 < \frac{1}{2d-1} \leq p_c \leq 0.8639 \] and for \(d=3\): \[ 0.2000 < \frac{1}{2d-1} \leq p_c \leq 0.8639 \] This allows to grasp the improvement brought later by Theorem 3.12.

Using the two following sequences of the On-Line Encyclopedia of Integer Sequences, one can evaluate the connective constant \(\kappa(d)\)

By taking the k-th root of of k-th term of A001411, we may give an approximation of \(\kappa(2)\):

sage: L = [1, 4, 12, 36, 100, 284, 780, 2172, 5916, 16268, 44100, 120292, 324932, 881500, 2374444, 6416596, 17245332, 46466676, 124658732, 335116620, 897697164, 2408806028, 6444560484, 17266613812, 46146397316, 123481354908, 329712786220, 881317491628] sage: for k in range(1, len(L)): print numerical_approx(L[k]^(1/k)) 4.00000000000000 3.46410161513775 3.30192724889463 3.16227766016838 3.09502148400370 3.03400133198980 2.99705187539871 2.96144397263395 2.93714926770637 2.91369345857619 2.89627439045790 2.87949308754677 2.86632078916860 2.85362749495679 2.84328447096562 2.83329615650289 2.82493415671599 2.81684125361654 2.80992368218258 2.80321554383456 2.79738645741910 2.79172363211806 2.78673687369245 2.78188437392354 2.77756387722633 2.77335345579129 2.76956977331575

By taking the k-th root of of k-th term of A001412, we may give an approximation of \(\kappa(3)\):

sage: L = [1, 6, 30, 150, 726, 3534, 16926, 81390, 387966, 1853886, 8809878, 41934150, 198842742, 943974510, 4468911678, 21175146054, 100121875974, 473730252102, 2237723684094, 10576033219614, 49917327838734, 235710090502158, 1111781983442406, 5245988215191414, 24730180885580790, 116618841700433358, 549493796867100942,2589874864863200574, 12198184788179866902, 57466913094951837030, 270569905525454674614] sage: for k in range(1, len(L)): print numerical_approx(L[k]^(1/k)) 6.00000000000000 5.47722557505166 5.31329284591305 5.19079831727404 5.12452137580198 5.06709510955294 5.02933019629493 4.99573287588832 4.97111339009676 4.94876680377358 4.93129192790635 4.91521453865211 4.90209314463520 4.88990167518413 4.87964724632057 4.87004597517131 4.86178722582108 4.85400655861169 4.84719703702142 4.84074902256992 4.83502763526502 4.82958688248615 4.82470487210973 4.82004549244633 4.81582557693112 4.81178552451599 4.80809774735294 4.80455755518719 4.80130435575213 4.79817388859565

Then, \(\kappa(2)\) would be something less than 2.769 and \(\kappa(3)\) would be something less than 4.798.

Thus, we may evaluate the lower bound and upper bound given at Theorem 3.12. For dimension \(d=2\):

sage: k < 2.76956977331575 k < 2.76956977331575 sage: _ / (2.76956977331575 * k) 0.361066909970928 < (1/k) sage: 1 - 0.361066909970928 0.638933090029072

The critical probability of bond percolation on \(\mathbb{L}^d\) with \(d=2\) satisfies \[ 0.3610 < \frac{1}{\kappa(2)} \leq p_c \leq 1 - \frac{1}{\kappa(2)} < 0.6389. \] If we look at the graph of the percolation probability \(\Theta(p)\) we did above for when \(d=2\), it seems that the lower bound is not far from \(p_c\). The lower bound 0.3610 is a small improvement to the simple one got from Theorem 3.2 (0.3333).

Similarly, for dimension \(d=3\):

sage: k < 4.79817388859565 k < 4.79817388859565 sage: _ / (4.79817388859565 * k) 0.208412621805310 < (1/k)

The critical probability of bond percolation on \(\mathbb{L}^d\) with \(d=3\) satisfies \[ 0.2084 < \frac{1}{\kappa(3)} \leq p_c \leq 1 - \frac{1}{\kappa(2)} < 0.6389. \] Again, if we look at the graph of \(\Theta(p)\) we did above for when \(d=3\), it seems that the lower bound 0.2084 is not far from \(p_c\). In this case, the lower bound 0.2084 is a rather small improvement to the lower bound from Theorem 3.2 (0.2000). It might be caused by a poor approximation of \(\kappa(3)\) from the above sequences of only 30 terms from the OEIS.

Below are some Sage tricks that I gathered from other users of Sage, from sage-devel and other places since one year.

**Stop the focus in the Notebook**

This *Notebook hack of the day* was published on sage-devel by William Stein
during May 2012 to fix that focus movement in the Notebook:

html('<script>cell_focus=function(x,y){} </script>')

**Consult the documentation of a function in the browser**

Open the documentation of a particular function in a web browser, from either the command-line or the notebook:

sage: browse_sage_doc(factor)

It works also for methods of an object:

sage: m = matrix(2, range(4)) sage: browse_sage_doc(m.inverse)

I found this command when I consulted the `help()`:

sage: help()

**Implicit multiplication**

Some behavior in Sage can be made implicit like multiplication and variable definition. This might be good for new users coming from Maple for instance.

Normally, this syntax raises an error:

sage: 34x ------------------------------------------------------------ File "<ipython console>", line 1 34x ^ SyntaxError: invalid syntax

It is possible to make it work:

sage: implicit_multiplication(True) sage: 34x 34*x

**Implicit variable definition**

The following works **only** in the Sage Notebook. It allows to turn on
automatic definition of variables:

sage: automatic_names(True) sage: x + y + z x + y + z

**Turn out automatic show when using plot**

Set the default to `False` for showing plots using any plot commands:

sage: show_default(False)

I prefer `False` but you may not.

**Rerun the patchbot**

One can re-run the tests of a particular ticket by adding `?kick` to the url
of the ticket on the patchbot Sage server. For example, to rerun the tests on
the ticket #13461, one can load the following page:

http://patchbot.sagemath.org/ticket/13461/?kick

This trick was shared on sage-devel during August 2012.

**Python debugger**

The majority of the Best Practices for Scientific Computing are followed by the Sage Development model. But, there is one principle that at least I do not use enough : a debugger. However, a Python debugger exists and a tutorial for using the Python debugger is available on onlamp.com.

I remember that discussion on sage-devel Poll: which debugger do you use? where developers were sharing their debugger tricks. It seems that using print statements is unavoidable.

**Computing basic statistics with R**

I always knew R is in Sage but never used it even if sometimes I need to compute some statistics of list of numbers. In Sage, one can print statistics of a list of numbers using R:

sage: L = [randint(0,100) for _ in range(20)] sage: r.summary(L) Min. 1st Qu. Median Mean 3rd Qu. Max. 14.00 27.75 57.50 53.45 69.00 98.00

**Creation of the number field in \(\sqrt{5}\)**

Before learning it from this video of William Stein, I did not know that the square brackets could be used to create such number field:

sage: A = ZZ[sqrt(5)] sage: a,sqrt5 = A.gens() sage: A Order in Number Field in sqrt5 with defining polynomial x^2 - 5 sage: sqrt5 sqrt5

**Using Sage locally in the notebook from a server**

First, log into the server using the following port setup:

ssh -L 8389:localhoat:8389 [SERVER]

Start the notebook with the given port:

sage -notebook port=8389

This ask for a password, if you forget it, you may reset it by first opening
Sage, and by starting the notebook with the option `reset=True`:

sage: notebook(port=8389, reset=True)

Then, by opening the browser at the following adress, I can log in to the notebook from the server:

http://localhost:8389/home/admin/

**Going from Mercurial to Git**

Sage will soon move from Mercurial to Git. In the past, I tried to understand the difference between Mercurial and Git. I was never able to find a simple text or blog post on the web explaining in a simple way the differences. One diffence would be about branching. But I was not using branches with Mercurial... As I see it, differences between Mercurial and Git are hard to explain or at least hard to understand.

Anyway, I once found this tutorial on the Git version control system:
Understanding Git Conceptually where the approach is "conceptual" and maybe
easier for the mathematician. For instance, in Section 1 it is written that
repositories can be "*visualized as a directed acyclic graph of commit
objects*". I still haven't go through this tutorial but I consider to start
with this one.

**Inheritance tree**

One may draw the inheritance tree of a class with the following command:

sage: class_graph(Integer).plot()

Let's first construct a graph that we will use in our examples below. We first construct a finite group generated by 2 by 2 matrices on the field \(GF(3)\). The group contains 24 elements. We then construct its Cayley graph:

sage: F = GF(3) sage: gens = [matrix(F,2,[1,0, 1,1]), matrix(F,2, [1,1, 0,1])] sage: group = MatrixGroup(gens); group Matrix group over Finite Field of size 3 with 2 generators: [[[1, 0], [1, 1]], [[1, 1], [0, 1]]] sage: group.cardinality() 24 sage: G = group.cayley_graph()

The default graph plot in Sage is:

sage: G.show(color_by_label=True)

Using `view` is actually broken when vertices are matrices because default
format (`format='tkz_graph'`) does not support it:

sage: view(G) An error occurred. ... LaTex error

One may get another kind of tikz output using the `dot2tex.spkg` together
with graphviz. To know what is the latest available version of dot2tex use
the command `optional_packages()`:

sage: [x for x in flatten(optional_packages()) if 'dot2tex' in x] ['dot2tex-2.8.7-2']

The command to install the most recent version of `dot2tex.spkg` do from the
command line (where you replace the version numbers by the above output):

sage -i dot2tex-2.8.7-2

As the documentation of `G.layout_graphviz()` says, install graphviz >= 2.14
so that the programs `dot`, `neato`, ... are in your path. The graphviz
suite can be download from the graphviz website.

This should allow the following to work:

sage: G.set_latex_options(format='dot2tex', prog='neato') sage: G.set_latex_options(color_by_label=True) sage: view(G)

With the above usage, you will find that the command `view(G)` command is
very slow and that sometimes it just doesn't work and gives a Latex error like
this:

sage: G.set_latex_options(format='dot2tex', prog='dot') sage: view(G) An error occurred. ... LaTex error

This is because the default compilation is just unappropriate for our usage (I
still wonder for which usage it can be appropriate). In fact, the default
compilation is first trying the conversion `tex` to `dvi` to `png` using
`latex` and `dvipng`. If the `dvipng` part does not work for whatever
reason (which is our case), it will then try the conversion `dvi` to `ps`
to `pdf` using `dvips` and `ps2pdf`. This worked above for
`prog='neato'` but not for `prog='dot'` because `dvipng` does not seem to
like when `latex` produces `Overfull \hbox` and `Overfull \vbox`.

The compilation strategy can be changed by using the `engine` option and by
setting it to `'pdflatex'`. Also the `Overfull` problem can be solved using
the option `tightpage=True`:

sage: G.set_latex_options(format='dot2tex', prog='dot') sage: G.set_latex_options(color_by_label=True) sage: view(G, engine='pdflatex', tightpage=True)

The variable `prog` is for the program used for the layout. It must be a
string corresponding to one of the software of the graphviz suite. Accepted
values for `prog` are:

'dot'(the default)'neato''twopi''circo''fdp'

When using `format='dot2tex'`, other available options are:

sage: G.set_latex_options(color_by_label=True) sage: G.set_latex_options(edge_labels=True) sage: G.set_latex_options(edge_colors=I_dont_know_what)

Consult the help for more details:

sage: opts = G.latex_options() sage: opts.set_option?

However, these other options do not seem to work perfectly. I don't know what
format to give to `edges_colors` and `edge_labels=True` seems broken. I
posted a workaround on the sagetrac to fix it.

Alternatively, when I get problems with the `view` command, I use my script
tikz2pdf instead:

sage: G.set_latex_options(format='dot2tex', prog='dot') sage: G.set_latex_options(color_by_label=True) sage: G.latex_options() LaTeX options for Digraph on 24 vertices: {'prog': 'dot', 'color_by_label': True, 'format': 'dot2tex'} sage: s = G.latex_options().dot2tex_picture() sage: f = open('graph_dot.tikz', 'w') sage: f.write(s) sage: f.close() sage: !tikz2pdf graph_dot.tikz Using template ... tikz2pdf: calling pdflatex... tikz2pdf: Output written to 'graph_dot.pdf'.

In version 5.3 of Sage, if the vertices of a graph are matrices, then the default latex output does not compile. The default format is a tikzpicture and uses the tkz-berge library. One solution is to change the format to dot2tex. See below.

The default tikz output is:

sage: m = matrix(3, range(9)) sage: m.set_immutable() sage: G = Graph() sage: G.add_vertex(m) sage: latex(G) \begin{tikzpicture} % \useasboundingbox (0,0) rectangle (5.0cm,5.0cm); % \definecolor{cv0}{rgb}{0.0,0.0,0.0} \definecolor{cfv0}{rgb}{1.0,1.0,1.0} \definecolor{clv0}{rgb}{0.0,0.0,0.0} % \Vertex[style={minimum size=1.0cm,draw=cv0,fill=cfv0,text=clv0,shape=circle}, LabelOut=false,L=\hbox{$\left(\begin{array}{rrr} 0 & 1 & 2 \\ 3 & 4 & 5 \\ 6 & 7 & 8 \end{array}\right)$},x=2.5cm,y=2.5cm]{v0} % % \end{tikzpicture}

This output does not compile. Here is the error I get:

sage: view(G) An error occurred. This is pdfTeX, Version 3.1415926-1.40.10 (TeX Live 2009) (format=pdflatex 2011.4.19) 18 OCT 2012 21:34 entering extended mode [...] ! Use of \tikz@@scope@env doesn't match its definition. \pgfutil@ifnextchar #1#2#3->\let \pgfutil@reserved@d =#1\def \pgfutil@reserved@a { #2}\def \pgf util@reserved@b {#3}\futurelet \pgfutil@let@token \pgfutil@ifnch l.54 \end{array}\right)$},x=2.5cm,y=2.5cm]{v0} If you say, e.g., `\def\a1{...}', then you must always put `1' after `\a', since control sequence names are made up of letters only. The macro here has not been followed by the required stuff, so I'm ignoring it. ! Use of \tikz@@scope@env doesn't match its definition. [...] ! ==> Fatal error occurred, no output PDF file produced! Latex error

The command to install dot2tex:

sage -i dot2tex-2.8.7-2

As the documentation of `G.layout_graphviz()` says, install graphviz >=
2.14 so that the programs dot, neato, ... are in your path.
This allows the following to work:

sage: m = matrix(3, range(9)) sage: m.set_immutable() sage: G = Graph() sage: G.add_vertex(m) sage: G.set_latex_options(format='dot2tex') sage: view(G)

To obtain the tikz code:

sage: tikz_string = G.latex_options().dot2tex_picture() sage: print tikz_string \begin{tikzpicture}[>=latex,line join=bevel,] %% \node (012345678) at (34bp,22bp) [draw,draw=none] {$\left(\begin{array}{rrr}0 & 1 & 2 \\3 & 4 & 5 \\6 & 7 & 8\end{array}\right)$}; % \end{tikzpicture}

Question :

Comment fait-on en sage pour avoir le terme général d'une serie formelle en \(x\) comme \(1/(1-q^2x)\) par exemple, où \(q\) est un paramètre (il faudrait obtenir \(q^{2k} x^k\) ) ?

Quelques exemples se trouvent dans la documentation sur les espèces en Sage, mais il faut faire quand même quelques essais et combiner quelques idées pour y parvenir. Une façon de procéder est définir une espèce récursive en assignant un poids pour le paramètre (voir Weighted Species).

Sous une forme récursive, la série s'écrit :

\[ L = 1 + q^2 \cdot x \cdot L \]

Alors, en sage, on écrira:

sage: q = QQ['q'].gen() sage: E = species.EmptySetSpecies() sage: X = species.SingletonSpecies(weight=q^2) sage: L = CombinatorialSpecies() sage: L.define(E+X*L) sage: L.generating_series().coefficients(10) [1, q^2, q^4, q^6, q^8, q^10, q^12, q^14, q^16, q^18]

Aussi:

sage: X.generating_series().coefficients(5) [0, q^2, 0, 0, 0] sage: E.generating_series().coefficients(5) [1, 0, 0, 0, 0]

On peut faire le produit de deux espèces:

sage: A = X * X sage: A.generating_series().coefficients(5) [0, 0, q^4, 0, 0]

On peut faire la somme de deux espèces:

sage: B = X + X sage: B.generating_series().coefficients(5) [0, 2*q^2, 0, 0, 0]

mais pas la différence:

sage: E - X Traceback (most recent call last) : ... TypeError: unsupported operand type(s) for -: 'EmptySetSpecies_class' and 'SingletonSpecies_class'

ni le quotient:

sage: E / X Traceback (most recent call last): ... TypeError: unsupported operand type(s) for /: 'EmptySetSpecies_class' and 'SingletonSpecies_class'

Encore moins une combinaison des deux:

sage: E/(E-X) Traceback (most recent call last) : ... TypeError: unsupported operand type(s) for -: 'EmptySetSpecies_class' and 'SingletonSpecies_class'

et je ne sais pas pourquoi...

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